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	<title>Newtons Laws EX 31 - Revision history</title>
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	<updated>2026-04-20T19:49:13Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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		<title>imported&gt;Patrick: Created page with &#039;There are four forces acting on this block: &lt;math&gt;F_G&lt;/math&gt;, &lt;math&gt;F_N&lt;/math&gt;, &lt;math&gt;F_f&lt;/math&gt;, &lt;math&gt;F&lt;/math&gt;. The block slides up the incline and therefore the force of kinet…&#039;</title>
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		<updated>2011-05-26T20:26:02Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;#039;There are four forces acting on this block: &amp;lt;math&amp;gt;F_G&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F_N&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F_f&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F&amp;lt;/math&amp;gt;. The block slides up the incline and therefore the force of kinet…&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;There are four forces acting on this block: &amp;lt;math&amp;gt;F_G&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F_N&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F_f&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;F&amp;lt;/math&amp;gt;. The block slides up the incline and therefore the force of kinetic friction points down the incline (because friction opposes motion).&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
[[image:N_APP_EX_31_SOLNa.png|TOP]]&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
We select the x-axis parallel to the incline and draw a free body diagram:&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
[[image:N_APP_EX_31_SOLNb.png|TOP]]&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The components of the forces exerted on the mass m = 5 kg are:&lt;br /&gt;
&lt;br /&gt;
{| border=&amp;quot;1&amp;quot; cellpadding=&amp;quot;2&amp;quot; style=&amp;quot;text-align:center&amp;quot;&lt;br /&gt;
|-&lt;br /&gt;
! Forces&lt;br /&gt;
! x-component&lt;br /&gt;
! y-component&lt;br /&gt;
|-&lt;br /&gt;
! &amp;lt;math&amp;gt;F_G&amp;lt;/math&amp;gt;&lt;br /&gt;
| 50 cos(-127°) = -30 N&lt;br /&gt;
| 50 sin(-127°) = -40 N&lt;br /&gt;
|-&lt;br /&gt;
! &amp;lt;math&amp;gt;F_N&amp;lt;/math&amp;gt;&lt;br /&gt;
| 0&lt;br /&gt;
| &amp;lt;math&amp;gt;F_N&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
! &amp;lt;math&amp;gt;F_f&amp;lt;/math&amp;gt;&lt;br /&gt;
| &amp;lt;math&amp;gt;-F_f&amp;lt;/math&amp;gt;&lt;br /&gt;
| 0&lt;br /&gt;
|-&lt;br /&gt;
! &amp;lt;math&amp;gt;F&amp;lt;/math&amp;gt;&lt;br /&gt;
| 25 cos(-37°) = 20 N&lt;br /&gt;
| 25 sin(-37°) = -15 N&lt;br /&gt;
|}&lt;br /&gt;
&amp;lt;br&amp;gt;&lt;br /&gt;
Note that we used &amp;lt;math&amp;gt;g = 10 m/s^2&amp;lt;/math&amp;gt; in our computations.&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
First we have to deal with the y-component. Writing&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;-40 - 15 + F_N = 0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
we see that &amp;lt;math&amp;gt;F_N = 55 N&amp;lt;/math&amp;gt;. Substituting this value for &amp;lt;math&amp;gt;F_N&amp;lt;/math&amp;gt; in the equation for the force of kinetic friction we get:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;F_{f_{max}} = \mu_K F_N = (0.1)(55) = 5.5 N&amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
Now, looking at the x-component, we write&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;-30 + 20 - 5.5 = 5 a&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Solving for &amp;lt;math&amp;gt;a&amp;lt;/math&amp;gt;, we find &amp;lt;math&amp;gt;a = -3.1 m/s^2&amp;lt;/math&amp;gt;.&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
To find the distance travelled in 2 s, we will use the equations of kinematics. The initial velocity is 6 m/s. We use the following equation for displacement:&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;\Delta x = v_i t + \frac{1}{2} a t^2&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Substituting, we find:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\Delta x = (6)(2) + \frac{1}{2}(-3.1)(2)^2 = 5.8 m&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>imported&gt;Patrick</name></author>
	</entry>
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