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	<id>https://euler.vaniercollege.qc.ca/gwikis/pwiki/index.php?action=history&amp;feed=atom&amp;title=Potential_Energy_EX_8</id>
	<title>Potential Energy EX 8 - Revision history</title>
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	<updated>2026-04-20T19:36:10Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://euler.vaniercollege.qc.ca/gwikis/pwiki/index.php?title=Potential_Energy_EX_8&amp;diff=585&amp;oldid=prev</id>
		<title>imported&gt;Patrick: Created page with &#039;The diagram below shows how the mass is being dropped onto the spring (fig. 1). It compresses the spring by 0.2 m (fig. 2) and then the spring decompresses while the mass moves u…&#039;</title>
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		<updated>2011-08-15T17:06:44Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;#039;The diagram below shows how the mass is being dropped onto the spring (fig. 1). It compresses the spring by 0.2 m (fig. 2) and then the spring decompresses while the mass moves u…&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;The diagram below shows how the mass is being dropped onto the spring (fig. 1). It compresses the spring by 0.2 m (fig. 2) and then the spring decompresses while the mass moves up 0.1 m (fig. 3).&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
[[image:Helena_Pot_Energy_Ex_8_Soln.png|TOP]]&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
 &lt;br /&gt;
The compression of the spring changes from the initial compression of &amp;lt;math&amp;gt;x_i = 0.2&amp;lt;/math&amp;gt; m to the final compression of the spring &amp;lt;math&amp;gt;x_f = 0.1&amp;lt;/math&amp;gt; m. We expect to find the total change in potential energy to be negative when the mass is released because it moves spontaneously in this direction.&lt;br /&gt;
The change in gravitational potential energy is positive since the mass moves up:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\Delta U = m g h = (0.1)(10)(0.1) = 0.1 J&amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
The change in the spring&amp;#039;s potential energy is&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\Delta U = \frac{1}{2} k {x_f}^2 - \frac{1}{2} k {x_i}^2 = \frac{1}{2}(50)(0.1)^2 - \frac{1}{2}(50)(0.2)^2 = -0.75 J&amp;lt;/math&amp;gt;&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
The total change in potential energy of this system is&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;\Delta U = -0.75 + 0.1 = -0.65 J&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>imported&gt;Patrick</name></author>
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