Nuzhat at 14:01, 17 August 2010

2010-08-17T14:01:46Z

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''Helena Dedic''

A projectile fired from the ground has a velocity of 24i -8j m/s at a height of 9.8 m. Find the initial velocity and the maximum height. 

'''Solution:''' 

[[image: Proj Motion Sol 11.png|TOP]] 

We know that <math>\Delta x = 1.6 m</math> and <math>\Delta y = -1.1 m</math>. 

We can find the initial velocity in the y-direction using equation 4: 

<math>v_y^2 - v_{yo}^2 = - 19.6 m/s^2 \Delta y</math>

<math>v_{yo}^2 = v_y^2 + 19.6 m/s^2 \Delta y</math>

<math>v_{yo}^2 = (-8 m/s)^2 + 19.6 m/s^29.8 m = 256.08 m^2/s^2</math>

<math>v_{yo} = 16m/s</math>

Knowing v_{yo}, we can find the maximum height, H, by setting <math>v_y = 0</math> in equation 4: 

<math>v_y^2 - v_{yo}^2 = - 19.6 m/s^2 \Delta y</math> 

<math>0 - v_{yo}^2 = - 19.6 m/s^2H</math> 

H = 13 m
 

*[[Projectile Motion|Back to Projectile Motion]] 
*[[Exercises on Projectile Motion|Back to Exercises on Projectile Motion]]

Proj Motion EX 11 - Revision history

Nuzhat at 14:01, 17 August 2010