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	<title>Proj Motion EX 12 - Revision history</title>
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		<title>Nuzhat: Created page with &#039;&#039;&#039;Helena Dedic&#039;&#039; &lt;br&gt;  A ball is thrown from ground level. Three seconds later it is moving horizontally at 15 m/s. Find the horizontal range and the angle of impact. &lt;br&gt; &lt;br&gt;  …&#039;</title>
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		<updated>2010-08-17T14:08:44Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;#039;&amp;#039;&amp;#039;Helena Dedic&amp;#039;&amp;#039; &amp;lt;br&amp;gt;  A ball is thrown from ground level. Three seconds later it is moving horizontally at 15 m/s. Find the horizontal range and the angle of impact. &amp;lt;br&amp;gt; &amp;lt;br&amp;gt;  …&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;#039;&amp;#039;Helena Dedic&amp;#039;&amp;#039;&lt;br /&gt;
&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
A ball is thrown from ground level. Three seconds later it is moving horizontally at 15 m/s. Find the horizontal range and the angle of impact. &amp;lt;br&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Solution:&amp;#039;&amp;#039;&amp;#039; &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
At t = 2 s, the velocity of a projectile is v = (15 m/s, 0 m/s). What is the range of the flight and the angle of impact?&lt;br /&gt;
&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
[[image: Proj Motion Sol 12.png|TOP]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Since &amp;lt;math&amp;gt;v_y = 0&amp;lt;/math&amp;gt;, the projectile must be at the top of its motion at t = 2 s. The total time of the motion is then 4 s and the range is given by equation 1:  &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;\Delta x = v_{xo}t&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt; \Delta x = 15 m/s * 4 s = 60 m&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Find the velocity in the y-direction at impact taking the initial velocity as zero at the top and finding the velocity 2 s later: &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;v_y = v_{yo} - 9.8 m/s^2 t&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;v_y = 0 - 9.8 m/s^2 2 s&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;v_y = - 19.6 m/s&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
The velocity at impact is v = (15 m/s, -19.6 m/s) so that the angle of impact is &amp;lt;math&amp;gt;52.6^o&amp;lt;/math&amp;gt; below the horizontal or &amp;lt;math&amp;gt;-52.6^o&amp;lt;/math&amp;gt;. &amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
*[[Projectile Motion|Back to Projectile Motion]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
*[[Exercises on Projectile Motion|Back to Exercises on Projectile Motion]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;/div&gt;</summary>
		<author><name>Nuzhat</name></author>
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