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	<title>Proj Motion EX 8 - Revision history</title>
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		<title>Nuzhat at 03:31, 17 August 2010</title>
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		<updated>2010-08-17T03:31:41Z</updated>

		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;#039;&amp;#039;Helena Dedic&amp;#039;&amp;#039;&lt;br /&gt;
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A plane flying horizontally dropped a supply of blankets for stranded hunters. The blankets landed 4 s after the drop with a speed of 50 m/s. &amp;lt;br&amp;gt;&lt;br /&gt;
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a.	What were the components of the velocity when the supply landed? &amp;lt;br&amp;gt;&lt;br /&gt;
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b.	What was the velocity of the plane? &amp;lt;br&amp;gt;&lt;br /&gt;
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c.	How high was the plane flying? &amp;lt;br&amp;gt;&lt;br /&gt;
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d.	How far did the blankets move in the horizontal direction? &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
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&amp;#039;&amp;#039;&amp;#039;Solution:&amp;#039;&amp;#039;&amp;#039; &amp;lt;br&amp;gt;&lt;br /&gt;
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The plane is flying horizontally with some speed v. The blankets, when dropped, move (initially) with the speed of the plane. &amp;lt;br&amp;gt;&lt;br /&gt;
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 Their initial velocity is therefore horizontal.&lt;br /&gt;
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Now, let us choose coordinate system with origin on the ground just below the drop point. The positive y-axis points upward and the positive x-axis points in the direction the plane is moving. &amp;lt;br&amp;gt;&lt;br /&gt;
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This means the y-component of initial velocity is 0 while the x-component is v. &amp;lt;br&amp;gt;&lt;br /&gt;
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The blankets follow parabolic path, and land 4 s later. Since the y-component of velocity decreases at a rate of - 10 m/s every second we know that the blankets land with vertical component of velocity equal to - 40 m/s. Moreover, we are told the speed of the blankets as they land is 50 m/s. Thus we know the magnitude and y-component of velocity. Consider the following picture: &amp;lt;br&amp;gt;&lt;br /&gt;
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[[image: Proj Motion Sol 8.png|TOP]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
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Thus let us draw &amp;lt;math&amp;gt;v_x&amp;lt;/math&amp;gt; - t and &amp;lt;math&amp;gt;v_y&amp;lt;/math&amp;gt; - t graphs and use these to solve the given problem:&amp;lt;br&amp;gt;&lt;br /&gt;
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[[image: Proj Motion Sol 8b.png|TOP]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
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a.	We know the magnitude of velocity is 50 m/s and the y-component is - 40 m/s. We solve for vx using the equation : &amp;lt;br&amp;gt;&lt;br /&gt;
 &amp;lt;math&amp;gt;v^2 = v_x^2 + v_y^2&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&lt;br /&gt;
 &amp;lt;math&amp;gt;v_x^2 = 50^2 - 40^2 = 900&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
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It follows that &amp;lt;math&amp;gt;v_x = 30 m/s&amp;lt;/math&amp;gt;, so the components of velocity at impact is (30, -40) m/s.&amp;lt;br&amp;gt;&lt;br /&gt;
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b.	The velocity of the plane is the same as the horizontal component of the velocity of the blankets i.e., 30 m/s. &amp;lt;br&amp;gt;&lt;br /&gt;
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c.	The vertical distance travelled by the blankets is the area under the triangle: ½ • 4 • (- 40) = - 80 m. The vertical displacement of the blankets is - 80 m so the plane flies at an altitude of 80 m. &amp;lt;br&amp;gt;&lt;br /&gt;
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d.	Since the horizontal velocity of the blankets was 30 m/s we conclude that they covered a horizontal distance of 120 m in 4 s.&amp;lt;br&amp;gt;&lt;br /&gt;
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*[[Projectile Motion|Back to Projectile Motion]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;br /&gt;
*[[Exercises on Projectile Motion|Back to Exercises on Projectile Motion]] &amp;lt;br&amp;gt;&amp;lt;br&amp;gt;&lt;/div&gt;</summary>
		<author><name>Nuzhat</name></author>
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