https://euler.vaniercollege.qc.ca/gwikis/pwiki/index.php?action=history&feed=atom&title=Work-Energy_Theorem_EX_1Work-Energy Theorem EX 1 - Revision history2026-04-20T21:10:59ZRevision history for this page on the wikiMediaWiki 1.43.0https://euler.vaniercollege.qc.ca/gwikis/pwiki/index.php?title=Work-Energy_Theorem_EX_1&diff=537&oldid=previmported>Patrick at 03:01, 4 August 20112011-08-04T03:01:18Z<p></p>
<p><b>New page</b></p><div>'''(a)''' Using the relationship for the change of kinetic energy <math>\Delta K = K_f - K_i = \frac{1}{2} m {v_f}^2 - \frac{1}{2} m {v_i}^2</math>, we find<br />
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<math>\Delta K = \frac{1}{2}(0.1)(18)^2 - \frac{1}{2}(0.1)(20)^2 = -3.8 J</math><br />
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'''(b)''' The work (or more precisely the net work) done is equal to the change in kinetic energy:<br />
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<math>W = \Delta K = -3.8 J</math></div>imported>Patrick