Helena Dedic
Let's draw a free body diagram:
Σ F y = 0 {\displaystyle \Sigma F_{y}=0} 0.5 T 1 − 30 N = 0 {\displaystyle 0.5T_{1}-30N=0} 0.5 T 1 = 30 N {\displaystyle 0.5T_{1}=30N} T 1 = 60 N {\displaystyle T_{1}=60N}
Σ F x = 0 {\displaystyle \Sigma F_{x}=0} 0.87 T 1 − T 2 = 0 {\displaystyle 0.87T_{1}-T_{2}=0} T 2 = 0.87 T 1 {\displaystyle T_{2}=0.87T_{1}} T 2 = 0.87 ( 60 N ) {\displaystyle T_{2}=0.87(60N)} T 2 = 52.2 N {\displaystyle T_{2}=52.2N}
