Newton's Second Law can be axpressed as
F → = m a → = d p → d t {\displaystyle {\vec {F}}=m{\vec {a}}={\frac {d{\vec {p}}}{dt}}} "During an interval of time a constant force acting on an object causes a change of momentum."
F → = Δ p → Δ t {\displaystyle {\vec {F}}={\Delta {\vec {p}} \over \Delta t}}
Δ p → = F → Δ t {\displaystyle \Delta {\vec {p}}={\vec {F}}\Delta t} Given
F → = 1000 cos ( 127 ∘ ) i ^ + 1000 sin ( 127 ∘ ) j ^ = − 600 i ^ + 800 j ^ N {\displaystyle {\vec {F}}=1000\cos(127^{\circ }){\hat {i}}+1000\sin(127^{\circ }){\hat {j}}=-600{\hat {i}}+800{\hat {j}}N} we can compute
Δ p → = ( − 600 i ^ + 800 j ^ ) ( 0.001 ) = − 0.600 i ^ + 0.800 j ^ N {\displaystyle \Delta {\vec {p}}=(-600{\hat {i}}+800{\hat {j}})(0.001)=-0.600{\hat {i}}+0.800{\hat {j}}N}
