Conservation of Momentum EX 2

Newton's Second Law can be axpressed as

$\overrightarrow{F}=m\overrightarrow{a}=\frac{d\overrightarrow{p}}{dt}$

"During an interval of time a constant force acting on an object causes a change of momentum."

$\overrightarrow{F}=\frac{\mathrm{\Delta }\overrightarrow{p}}{\mathrm{\Delta }t}$

$\mathrm{\Delta }\overrightarrow{p}=\overrightarrow{F}\mathrm{\Delta }t$

Given

$\overrightarrow{F}=1000\cos (127^{\circ })\hat{i}+1000\sin (127^{\circ })\hat{j}=-600\hat{i}+800\hat{j}N$

we can compute

$\mathrm{\Delta }\overrightarrow{p}=(-600\hat{i}+800\hat{j})(0.001)=-0.600\hat{i}+0.800\hat{j}N$